Question

80 kg of an alloy X is mixed with 50 kg of an alloy Y. If alloy X has lead and copper in the ratio 3:7 and alloy Y
has lead and copper in the ratio 7:3, what is the amount of lead in the new alloy?​

Answer 1

Given :- 80 kg of an alloy X is mixed with 50 kg of an alloy Y. If alloy X has lead and copper in the ratio 3:7 and alloy Y has lead and copper in the ratio 7:3, what is the amount of lead in the new alloy ?

Solution :-

Alloy X :-

• Lead : copper = 3 : 7
• Lead = 80 * (3/10) = 24 kg .
• Copper = 80 * (7/10) = 56 kg.

Alloy Y :-

• Lead : copper = 7 : 3
• Lead = 50 * (7/10) = 35 kg .
• Copper = 50 * (3/10) = 15 kg.

Therefore,

→ Lead in new alloy = Lead in alloy X + Lead in alloy Y = 24 + 35 = 59 kg. (Ans.)

Hence, 59 kg of Lead is in the new alloy.

Learn more :-

what is the sum (in Rs) which when divided among A, B, C, D in the proportion 2:3:5:8 provides Rs 8420 less to D the wha...

https://brainly.in/question/26704366

two vessels x and y of capacities one and two litres respectively and completely filled with mixtureof two chemicals a a...

https://brainly.in/question/26618169