Question

80 L mixture of milk and water contains 25% of water. If24Lof mixture taken out from mixture, then find
what quantity of water should be mixed in remaining mixture to make water 65% of resulting mixture?
1.56L
2.44L
3.42L
4.40L
5.64L

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Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

Before taken out:

Volume of mixture or solution = 80L

Volume of water = 25L

Weight of water = volume of water×density of water

Weight of water = 25L×(10³g/L)

[We know, density of water = 1g/mL = 10³g/L]

Weight of water = 25×10³g

Molar mass of water = 18g/mol

Molarity(M) = weight of water/(molar mass×volume of solution)

M = (25×10³)/(18×80)

M = 17.36mol/L

After taken out:

Volume of mixture or solution = 80-24= 56L

Molarity or concentration of water will not change i.e. no. of moles of water per liter will be same.

Weight of water in 56L mixture or solution =

Molarity×molar mass of water×volume of solution

Weight of water in 56L mixture or solution =

17.36×18×56 = 17498.88g = 17.49×10³g

Volume of water in 56L mixture or solution =

Weight of water/density of water

Volume of water in 56L mixture or solution =

(17.49×10³g)/(10³g/L) = 17.49L

Volume of milk in mixture or solution =

56-17.49 = 38.51L

If we take 65% water, Volume of water(v):

(65/100)×volume of solution(solution which contains 65% water) = total volume of water(v)

[We know, volume of solution = volume of solute+volume of solvent]

(65/100)×(total volume of water(v)+volume of milk) = total volume of water(v)

(65/100)×(v+38.51) = v

65(v+38.51) = 100v

65v+2503.15 = 100v

35v = 2503.15

v = 71.51L

We get, total volume of water in 65% solution = 71.51L

Total volume of water = (volume of added water+water which is already present) in 56L of mixture

71.51 = volume of added water + 17.49

Volume of added water = 54.02 L

The quantity of water should be mixed in remaining mixture to make water 65 percent resulting mixture is 54.02L.