80 L mixture of milk and water contains 25% of water. If24Lof mixture taken out from mixture, then find
what quantity of water should be mixed in remaining mixture to make water 65% of resulting mixture?
1.56L
2.44L
3.42L
4.40L
5.64L
Answers
Answer:
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Answer:
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Step-by-step explanation:
Before taken out:
Volume of mixture or solution = 80L
Volume of water = 25L
Weight of water = volume of water×density of water
Weight of water = 25L×(10³g/L)
[We know, density of water = 1g/mL = 10³g/L]
Weight of water = 25×10³g
Molar mass of water = 18g/mol
Molarity(M) = weight of water/(molar mass×volume of solution)
M = (25×10³)/(18×80)
M = 17.36mol/L
After taken out:
Volume of mixture or solution = 80-24= 56L
Molarity or concentration of water will not change i.e. no. of moles of water per liter will be same.
Weight of water in 56L mixture or solution =
Molarity×molar mass of water×volume of solution
Weight of water in 56L mixture or solution =
17.36×18×56 = 17498.88g = 17.49×10³g
Volume of water in 56L mixture or solution =
Weight of water/density of water
Volume of water in 56L mixture or solution =
(17.49×10³g)/(10³g/L) = 17.49L
Volume of milk in mixture or solution =
56-17.49 = 38.51L
If we take 65% water, Volume of water(v):
(65/100)×volume of solution(solution which contains 65% water) = total volume of water(v)
[We know, volume of solution = volume of solute+volume of solvent]
(65/100)×(total volume of water(v)+volume of milk) = total volume of water(v)
(65/100)×(v+38.51) = v
65(v+38.51) = 100v
65v+2503.15 = 100v
35v = 2503.15
v = 71.51L
We get, total volume of water in 65% solution = 71.51L
Total volume of water = (volume of added water+water which is already present) in 56L of mixture
71.51 = volume of added water + 17.49
Volume of added water = 54.02 L
The quantity of water should be mixed in remaining mixture to make water 65 percent resulting mixture is 54.02L.