Math, asked by alka8832, 10 months ago

80 litres of a mixture contains milk and water in the ratio of 27 : 5. How much
more water is to be added to get a mixture containing milk and water in the
ratio of 3:1?
(A)
10 litres
(B)
15 litres
(C)
20 litres
(D)
None of these
बेचकर
मनाफा कमाया। उसने 100 काया​

Answers

Answered by ishu51320
0

Answer:

Answer is None of these tell me is this right

Answered by jitendra420156
0

Therefore 10 liter of water must be added to get required mixture.

Step-by-step explanation:

Given that, 80 liter of a mixture contains milk and water in the ratio 27:5

The amount of milk in the mixture =(\frac{27}{27+5} \times 80) liter

                                                         =(\frac{27}{32} \times 80) liter

                                                        =67.5 liter

The amount of water in the mixture =(\frac{5}{27+5} \times 80) liter

                                                         =(\frac{5}{32} \times 80) liter

                                                         =12.5 liter

Let x liter of water is to be added to get mixture of milk and water in ratio of 3:1

According to the problem,

\frac{67.5}{12.5+x} =\frac{3}{1}

\Rightarrow 3(12.5+x)=67.5 \times 1

\Rightarrow 37.5+3x= 67.5

\Rightarrow 3x = 67.5-37.5

\Rightarrow 3x =30

\Rightarrow x=\frac{30}{3}

\Rightarrow x=10

Therefore 10 liter of water is to be added to get mixture of milk and water in ratio of 3:1.

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