80 litres of a mixture contains milk and water in the ratio of 27 : 5. How much
more water is to be added to get a mixture containing milk and water in the
atio of 3:1 ?
1)
10 litres
(B)
15 litres
?
9
20 litres
(DY None of these
Answers
Step-by-step explanation:
27x litres and 5x litres of water = 80 litres of adulterated milk.
27x+5x= 32x = 80, or x = 2.5 litres.
It means that for 67.5 litres of milk there is 12.5 litres of water.
To adulterate the milk further you want to add w litres of water. So we have
67.5 : (12.5+w) = 3 : 1, or
67.5 = 3(12.5+w) = 37.5 + 3w, or
3w = 67.5–37.5 = 30, or
w = 10
So add another 10 litres of water (hope you do not collect it from the gutter!) to the mixture to get 67.5 litres of milk and 22.5 litres of water which is a ratio of 3:1.
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Answer:
27x litres and 5x litres of water = 80 litres of adulterated milk.
27x+5x= 32x = 80, or x = 2.5 litres.
It means that for 67.5 litres of milk there is 12.5 litres of water.
To adulterate the milk further you want to add w litres of water. So we have
67.5 : (12.5+w) = 3 : 1, or
67.5 = 3(12.5+w) = 37.5 + 3w, or
3w = 67.5–37.5 = 30, or
w = 10
So add another 10 litres of water to the mixture to get 67.5 litres of milk and 22.5 litres of water which is a ratio of 3:1.
therefore option a is the right option
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