Question

80 मीटर ऊँचाई से एक गेंद गिराई जाती चौथे सेकंड में तय दूरी​

Answer 1

Answer:

36 is the answer of this question

Answer 2

The distance traveled by the ball in 4th seconds is 34.3 m.

Explanation:

To calculate the distance covered, use the formula the distance traveled in t`th seconds as

$s_t_h=u+\frac{1}{2} g(2t-1)$

Here, s is the distance traveled in t second and u is the initial velocity of the ball and g is the acceleration due to gravity.

As ball drop from the height, so we take u = 0 and given t =4 s  and $g = 9.8m/s^2$.

Substitute the given values, we get

$S_{4th} =0+\frac{1}{2} 9.8m/s^2\times(2\times4-1)$

$S_{4th} =34.3m$

Thus, the distance traveled by the ball in 4th seconds is 34.3 m.

#Learn More: equation of motion.

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