80 railway wagons all of same mass 5x10^3 kg are pulled by an engine with a force of 4x10^5N the tension in the coupling between of 30th and 31th wagon from the engine is
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80 railway wagons all of same mass 5x10^3 kg are pulled by an engine with a force of 4x10^5N the tension in the coupling between of 30th and 31th wagon from the engine is?
Given:
- Mass of each wagon = 5×10³ kg
- Force applied on the engine = 4×10^5 N
Soln:
Total mass of 80 wagons = 80 × 5 × 10³ kg
ma = 4×10^5
a=1 m/s²
So , weagon the right side which produces tension!
⚽ T = 50 × one wagon mass × a
⚽T = 50 × 5 ×10³×1
⚽T = 25 × 10⁴ N
Therefore,
The tension in the coupling between of 30th and 31th wagon from the engine is 25 × 10⁴N!!!
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➭ Questíon :-
80 railway wagons all of same mass 5x10³ kg are pulled by an engine with a force of 4x10⁵ N the tension in the coupling between of 30th and 31th wagon from the engine is
➭ Given :-
Mass of each wagon = 5 × 10³kg
Froce applied on the engine = 4 × 10⁵N
➭ To find :-
The tension in the coupling between of 30th and 31th wagon from the engine
➭ Solution :-
→ Total mass of wagons
= 80 × 5 × 10³kg = 4 × 10³kg
so,wagon to the right side wide produces tension
Hence, the tension in the coupling between of 30th and 31th wagon from the engine is 25 × 10⁴N
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➝ MoRe to know....♪♪
- The tension force is the force that is transmitted through a string, rope, cable or wire when it is pulled tight by forces acting from opposite ends.
- The tension force is directed along the length of the wire and pulls equally on the objects on the opposite ends of the wire.
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