Question

80.
समीकरण
$6(x {}^{2} + 1 ) = 13x$
के मूल है।​

Answer 1

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$6 ({x}^{2} + 1) = 13x$

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$6( {x}^{2} + 1) = 13$

$6 {x}^{2} + 6 = 13$

$6 {x}^{2} = 13 - 6$

$6 {x}^{2} = 7$

$x = ±\sqrt{ \frac{7}{6} }$

Hope it helps you..!!!

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