Chemistry, asked by Anonymous, 6 months ago

80. Three particles of equal masses are placed
at the corners of an equilateral triangle, as
shown in fig. Now particle A starts with a
velocity v, towards line AB, particle B starts
with a velocity v, towards line BC and
particle C starts with velocity v, towards
line CA. The displacement of C.M. of three
particle A, B and C after time "t" will be
(given if v1 = V2 = v3)​

Answers

Answered by krishikumar210606
0

Answer:

Explanation:

80. Three particles of equal masses are placed

at the corners of an equilateral triangle, as

shown in fig. Now particle A starts with a

velocity v, towards line AB, particle B starts

with a velocity v, towards line BC and

particle C starts with velocity v, towards

line CA. The displacement of C.M. of three

particle A, B and C after time "t" will be

(given if v1 = V2 = v3)​

Answered by ItzYourHeartbeat
1

80. Three particles of equal masses are placed

at the corners of an equilateral triangle, as

shown in fig. Now particle A starts with a

velocity v, towards line AB, particle B starts

with a velocity v, towards line BC and

particle C starts with velocity v, towards

line CA. The displacement of C.M. of three

particle A, B and C after time "t" will be

(given if v1 = V2 = v3)

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