Question

₹800 becomes ₹956 in 3 year at a certain rate of interest. if the rate of interest is increased by 4% what amount will ₹800 become in 3 year​

Answer 1

Answer :

• 1052 amount will Rs.800 become in 3 year

Given :

• ₹800 becomes ₹956 in 3 years at a certain rate of interest ,if the rate of interest is increased by 4%

To find :

• what amount will ₹800 become in 3 year

Solution :

Given

• P = Rs.800 (principle)
• A = Rs.956(Amount)
• T = 3 years(Time)

We need to find the simple interest

Given, Rs.800 becomes ₹956 so,

⤍SI = 956 - 800

⤍ SI = Rs.156

Simple interest is Rs.156

Now, we need to find the rate :

As we know that,

• Simple interest = prt / 100

Where,

• p is principal
• r is rate
• t is time

⤍ SI = p × r × t / 100

⤍ 156 = (800 × r × 3) / 100

⤍ 156 = 2400 × r / 100

⤍ 156 = 24r

⤍ r = 156/24

⤍ r = 6.5 %

Rate is 6.5 %

Given,

If the rate of interest is increased by 4% what amount will ₹800 become in 3 year so,

• r = 6.5 + 4 = 10.5 %

we need to find the amount will Rs.800 becomes in 3 Years so,

• ⤍ p = 800
• ⤍ t = 3 years
• ⤍ r = 10.5

We know that,

• SI = prt/100

Where,

• Where,p is principal
• r is rate
• t is time

⤍ SI = 800 × 10.5 × 3 / 100

⤍ SI = 25200/100

⤍ SI = 252

⤍ Amount = 252 + 800 = 1052

Hence , 1052 amount will Rs.800 become in 3 year

Answer 2

Answer:

The amount = ₹ 1052

Step-by-step explanation:

Case 1:

Principal ( P ) = ₹ 800

Amount ( A ) = ₹ 956

Therefore,

  S.I = A - P

       = ₹ 956 - ₹ 800

       = ₹ 156

Rate % p.a. = $\frac{S.I*100}{P*T}$

               = $\frac{156*100}{800*3}$

               = 6.5 %

Case 2:

Principal ( P ) = ₹ 800

Time ( T ) = 3 years

Rate ( R ) = 6.5 % + 4 % = 10.5 %

Amount ( A ) = P + S.I

                     = ₹ 800 + $\frac{P*T*R}{100}$

                     = ₹ 800 + $\frac{800*10.5*3}{100}$

                     = ₹ 800 +  ₹ 252

                     = ₹ 1052

Therefore, The amount = ₹ 1052