Question

800 calories are supplied to large block of ice of 0oC. How much ice will melt

Answer 1

heat=800cal

800cal=4.2*800J

• 3360J

hfg (latent heat of fusion of ice) = 334 KJ

$Heat=mhfg$

3360=m334

m=3360/334

m=10.06Kg

hope this will helpfull to you

please mark as brainliest