800 kg of mortar consists of 55% sand, 33% cement and rest lime. What is the ratio of sand, cement and lime in the mortar?
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Answer:
Answer:
96 kg
Step-by-step explanation:
800 kg of mortar consists of :
Sand=55%
Cement = 33%
Rest is lime
So Lime = 100%-(55+33)%=12%
So, Amount of lime = 12\% \times 80012%×800
Amount of lime = \frac{12}{100} \times 800
100
12
×800
Amount of lime = 9696
Hence the mass of lime in mortar is 96 kg
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