Question

800 kilowatt hours in 2 months ( kilowatt hours per year)

Answer 1

Answer:

4800 hours is your answer.

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Step-by-step explanation:

800 : 2

=> 1 year = 12 months

=> $\frac{800 * 6}{2 * 6}$ = $\frac{4800}{12}$ = 4800 : 12