8000 for 12 children and 3 adults. The admission was 6000 for 8 children and 3 adults in another music concert. how much was the admission for each child and adult
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Answer:
14000 is the correct sum
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solution is provided below,
Let adult be "a" and children be "c".
so the equations will be formed as,
12c+3a= 8000 ---(1)
8c+3a= 6000 ---(2)
subracting the two equations,
4c= 2000
c= 500 ---(3)
substituting the value of equation (3) in equation (2), gives,
8x500+ 3a= 6000
3a= 2000
a= 2000/3
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