Question

8000 kg engine pulls a train of 5 wagons each of 2000 along a horizontal track with engine exerts a force of 4000 newton and the track offers a friction force of 5000 newton then calculate a the net accelerating force be the acceleration of the train see the force of wagon 1 on banking 2

Answer 1

Answer:

Correction:The force exerted by engine will be 40000N

,for the motion of a train the force exerted by engine should be greater then that of friction... In case if friction is greater then the force exerted by engine then there will be no motion...

a) The net accelerating force = 35000N

a) The net accelerating force = 35000N(b) The acceleration of train = 1.944 ms–2

a) The net accelerating force = 35000N(b) The acceleration of train = 1.944 ms–2(c) The force of wagon 1 on 2 = 1552 N

Explanation:

Given, force of engine = 40000 N

Force of friction = 5000 N

Mass of engine = 8000 kg

Total weight of wagons = 5 x 2000 kg = 10000 kg

(a) The net accelerating force

= Force exerted by engine – Force of fricition

= 40000 N – 5000 N = 35000 N

(b) The acceleration of the train

We know that, F = mass x acceleration

Or, 35000 N = (mass of engine + mass of 5 wagons) X a

Or,

35000

N=(8000kg+10000kg)×a

Or, 35000N=18000kg×a

a=35000N/18000kg=1.944ms−2

(c) The force of wagon 1 on wagon 2 =

mass of four wagons x acceleration

F=4×2000 kg×1.944ms−2

F=8000kg×1.944ms−2

F=1552N