8000 kg engine pulls A train of 5 Wagons each of 2000 kg along a horizontal track if the engine exerts a force of 4000 n and track the offers of friction force of 5000 and then calculate the following questions
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Mass of the engine = 8000 kg
Mass of each wagon = 2000 kg,
Np. of wagons = 5
Total mass of train = 8000+2000×5= 18000 kg
Force, F = 40000 N
Track resistance , R = 5000 N
Total accelerating force = F −R =40000−5000=35000 N
Let acceleration = x m/s²
Acceleration , = Accelerating force / mass
x=35000/18000= 35/18=1.94 m/s²
Frictional resistance of 4 wagons = 5000×(2000×4)/18000 =2222 .22 N
Accelerating force on 4 wagons =2000×4×1.944 =15552 N
Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance
=2222 .22 +15552=17774.22 N
Total force required to produce
Mass of the engine = 8000 kg
Mass of each wagon = 2000 kg,
Np. of wagons = 5
Total mass of train = 8000+2000×5= 18000 kg
Force, F = 40000 N
Track resistance , R = 5000 N
Total accelerating force = F −R =40000−5000=35000 N
Let acceleration = x m/s²
Acceleration , = Accelerating force / mass
x=35000/18000= 35/18=1.94 m/s²
Frictional resistance of 4 wagons = 5000×(2000×4)/18000 =2222 .22 N
Accelerating force on 4 wagons =2000×4×1.944 =15552 N
Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance
=2222 .22 +15552=17774.22 N
Total force required to produce
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