8000 kg engine pulls A train of 5 Wagons each of 2000 kg along horizontal track if the engine exerts a force of 40000 Newton and the track offers a friction force of 5000 Newton then calculate (I) net accelerating force
(2) acceleration of the train
(3) force of Wagon 1 on Wagon 2
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(1)
As the force applied by the train and frictional force are in opposite direction.
Net force = force exerted by train - frictional force
F =40000 - 5000
F =35000 N
(2)
Acceleration = Net driving force ÷ Total mass to be pulled
a = 35000 ÷ (8000 +5×2000)
a = 35000 ÷ 18000
a = 1.94 = 2m/s^2
(3)
F = m×a
Wagon 1 pulls a mass of 4 wagons behind it so to calculate force of wagon 1 on 2 mass we will take mass of all the 4 wagons behind it.
F =(4×2000) × 2
F = 16000N
Hope this helps...
✌
As the force applied by the train and frictional force are in opposite direction.
Net force = force exerted by train - frictional force
F =40000 - 5000
F =35000 N
(2)
Acceleration = Net driving force ÷ Total mass to be pulled
a = 35000 ÷ (8000 +5×2000)
a = 35000 ÷ 18000
a = 1.94 = 2m/s^2
(3)
F = m×a
Wagon 1 pulls a mass of 4 wagons behind it so to calculate force of wagon 1 on 2 mass we will take mass of all the 4 wagons behind it.
F =(4×2000) × 2
F = 16000N
Hope this helps...
✌
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