8086 prefetches only when at least ------------ bytes are free in queue. A) 4 b) 3 c) 2 d) 1
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Answer:
4 is a correct answer
Explanation:
1 bytes = 1024
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Explanation:
8086 pre-fetches only when at least 2 bytes are free in queue. Hence the correct answer is C. The 8086 architecture consists of a 6-byte pre-fetch instruction pipeline. The Execution Unit is running current instruction. The unit of bus interface in advance reads up to 6 bytes of the op-codes from memory. The 6 bytes long queue was selected as it is the maximum number of bytes that is required for the instruction in 8086.
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