Question

80a +120b=1 and 84a+112b=1 solve the problem using substitution method​

Answer 1

Step-by-step explanation:

80a+120b=1.......(1)

84a+112b=1.........(2)

then in eqn 1

80a= 1-120b

a=1-120b/80........(3)

the eqn 3 put in eqn 2

84(1-120b/80)+112b=1

84-10080b/80+112b=1

84-1008b/8+112b=1

84-1008b+112b=8

84-896b=8

-896b=-76

b=896/76

b=12

similarly put the value of b in eqn 1

80a+120(12)=1

80a+1440=1

80a=-1439

a=18