Question

80F capacitor is connected to 50V battery capacitor is dissconnected from battery and connect other uncharge 320F capacitor calculate charge on 2nd capacitor

Answer 1

4000coloumb is your required answer

Answer 2

Hey there!

Charge on first capacitor = Q₁ = C₁V₁

                                               = 80u × 50

                                               = 4000u C

                                               = 4m C

Common Potential [After connecting them together]

V = total charge / sum of capacitance

   = (Q₁ + Q₂)/C₁ + C₂

   = 4 × 10⁻³/(80+320) × 10⁻⁶

   = (4/400) × 10³

   = 1000/100

    = 10 V

Now, Charge on 2nd capacitor  : = C₂V

                                                   = 320u × 10

                                                   = 3200 u C

                                                   = 3.2m C 

Hope It Helps You!