80g of glucose is dissolved in 36.00g of water in a beaker. The total number of oxygen atoms in the solution is ??
Answers
Answered by
1
Molar mass of glucose (C₆H₁₂O₆) = 180 g
In 180 g of glucose there are 6 mol of oxygen atoms
Then,
In 80 g of glucose there will be 0.6 mol of oxygen atoms
Molar mass of water (H₂O) = 18 g
In 18 g of water there are 1 mol of oxygen atoms
Then,
In 36 g of water there will be 2 mol of oxygen atoms
Total number of oxygen atoms = 0.6 mol + 2 mol
= 2.6 mol
= 2.6 × 6.022 × 10²³ atoms
= 1.57 × 10²⁴ atoms
∴ There are 1.57 × 10²⁴ oxygen atoms in the solution.
In 180 g of glucose there are 6 mol of oxygen atoms
Then,
In 80 g of glucose there will be 0.6 mol of oxygen atoms
Molar mass of water (H₂O) = 18 g
In 18 g of water there are 1 mol of oxygen atoms
Then,
In 36 g of water there will be 2 mol of oxygen atoms
Total number of oxygen atoms = 0.6 mol + 2 mol
= 2.6 mol
= 2.6 × 6.022 × 10²³ atoms
= 1.57 × 10²⁴ atoms
∴ There are 1.57 × 10²⁴ oxygen atoms in the solution.
Similar questions