Question

[(81^1/2 × (64^1/3 + 125^1/3)]^1/4

Answer 1

81^1/2 can be written as √81.

√81 =9

64^1/3 can be written as 3√64

3√64 = 4

125^1/3 can be written as 3√125

3√125 = 5

therefore

[9× (4+5)]^1/4

[9×9]^1/4

81^1/4 can be written as 4√81.

4√81= 3.

Therefore the value is 3.

Thank you!!
☘️☘️☘️☘️☘️☘️
All the best.☺️

Answer 2

Hey friend,
Here is the answer you were looking for:
${(( {81}^{ \frac{1}{2} } \times ( {64}^{ \frac{1}{3} } + {125}^{ \frac{1}{3} }) )}^{ \frac{1}{4} } \\ \\ = ( {9}^{2 \times \frac{1}{2} } \times ( {4}^{3 \times \frac{1}{3} } + {5}^{3 \times \frac{1}{3} } )^{ \frac{1}{4} } \\ \\ = (9 \times (4 + 5)) \frac{1}{4} \\ \\ = {(9 \times 4 + 9 \times 5)}^{ \frac{1}{4} } \\ \\ = {(36 + 45)}^{ \frac{1}{4} } \\ \\ = {(81)}^{ \frac{1}{4} } \\ \\ = { {(3}^{4}) }^{ \frac{1}{4} } \\ \\ = {3}^{4 \times \frac{1}{4} } \\ \\ = 3$


Hope this helps!!!

@Mahak24

Thanks....
☺☺