Question

[81^1/2(64^1/3+125^1/3)]^1/4

Answer 1

Answer:

$[81^{\frac{1}{2}} (64^{\frac{1}{3}} + 125^{\frac{1}{3}})]^{\frac{1}{4}} = 3$

Step-by-step explanation:

[81^1/2(64^1/3+125^1/3)]^1/4

$[81^{\frac{1}{2}} (64^{\frac{1}{3}} + 125^{\frac{1}{3}})]^{\frac{1}{4}}$

81 = 9²

64 = 4³

125 = 5³

Using these

$= [(9^2)^{\frac{1}{2}} ((4^3)^{\frac{1}{3}} + (5^3)^{\frac{1}{3}})]^{\frac{1}{4}}  \\ \\= [9 (4 + 5)]^{\frac{1}{4}} \\= [ 9 (9)]^{\frac{1}{4}} \\\\= [81]^{\frac{1}{4}} \\\\= [3^4]^{\frac{1}{4}} \\ \\= 3$

$[81^{\frac{1}{2}} (64^{\frac{1}{3}} + 125^{\frac{1}{3}})]^{\frac{1}{4}} = 3$

Answer 2

Step-by-step explanation:

hey mate hope it is helpful to you