Question

[81^1/2( 64^1/3 +125^1/3)^3)^1/4​

Answer 1

Answer:

answer is=9

Step-by-step explanation:

$( ({81})^{ \frac{1}{2} } {{({64}^{ \frac{1}{3} } + {125}^{ \frac{1}{3} } })^{3} })^{ \frac{1}{4} } \\ = (( \sqrt{81} ) {{ ( \sqrt[3]{64} + \sqrt[3]{125} ) }^{ 3} })^{ \frac{1}{4} } \\ = (9 \times {{(4 + 5)}^{3} )}^{ \frac{1}{4} } \\ = ({9 \times 9 \times 9 \times 9})^{ \frac{1}{4} } \\ = \sqrt[4]{9 \times 9 \times 9 \times 9} \\ = 9$

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