Question

81 ^ 1/log 5 base 3 +27^log 9 base 36 +3^4/log 7base 9​

Answer 1

Answer:

890

Step-by-step explanation:

   $81^{log_{3}5}+27^{log_{9}36}+3^{log_{9}7}$

=  $3^{4(log_{3}5)}+3^{(3)\frac{2}{2} (log_{3}6)} +3^{4(\frac{1}{2}log_{3}7 )}$

=   $[3^{log_{3}5}]^{4}+[3^{log_{3}6}]^{3}+[3^{log_{3}7}]^{2}$

=   $5^{4}+6^{3}+7^{2}$

=   890.