Question

81^-2 / 729^1-x = 9^2x​

Answer 1

Step-by-step explanation:

$\frac{ {81}^{ - 2} }{ {729}^{1 - x} } = {9}^{2x}$

$=> \frac{{ ({3}^{4} })^{ - 2} }{ {({3}^{6} )}^{1 - x} } = { {(3}^{2} })^{2x}$

$=> \frac{{3}^{ - 8} }{ {3}^{6- 6x} } = {3}^{4x}$

$=> {3}^{{ - 8 - (6- 6x)}} = {3}^{4x}$

compare the power of 3 both side

=> -8-6+6x=4x

=> 2x=14

=> x=7 (ans)