Question

81^2+729^(1-x)=9^2x find the value of x​

Answer 1

Answer:

$81^{2} + 729^{(1-x)} = 9^{2x}$

$3^{4}^{(2)} + 3^{6}^{(1-x)} = 3^{2} ^{(2x)}$

$3^{8} + 3^{(6-6x)} = 3^{(4x)}$

As we have same base in the equation, now in powers

8+ 6 - 6x = 4x

14 -6x= 4x

10x = 14

x=1.4