Question

81,237 find the Euclid division lemma​

Answer 1

Step-by-step explanation:

81 )237(2

162

75)81(1

75

6)75(12

72

3)6(2

6

0

LCM=3.

Answer 2

$\large \bold{ \underline{ \underline{ \: Answer : \: \: \: }}}$

$\to$ HCF of 81 and 237 is 3

$\large \bold{ \underline{ \underline{ \: Explaination : \: \: \: }}}$

Since 237 > 81 , we apply division lemma to 237 and 81

$\to$ 237 = 81 × 3 + 6

We consider the new divisor 81 and new reminder 6 and apply the division lemma

$\to$ 81 = 6 × 13 + 3

We consider the new divisor 6 and new reminder 3 and apply the division lemma

$\to$ 6 = 3 × 2 + 0

The remainder has now become zero , so our procedure stops

Since the divisior at this stage is 3

Therefore , the HCF of 81 and 237 is 3