Question

(81)½-(64)-⅔ evaluate

Answer 1

Hey friend,
Here is the answer you were looking for:
${(81)}^{? \frac{1}{2} } - {(64)}^{ - \frac{2}{3} }$

We can also write is as :

${( {9}^{2} )}^{ \frac{1}{2} } - {( {4}^{3} )}^{ - \frac{2}{3} } \\ \\ = {9}^{2 \times \frac{1}{2} } - {4}^{3 \times - \frac{2}{3} } \\ \\ = 9 - {4}^{ - 2} \\ \\ = 9 - \frac{1}{ {4}^{2} } \\ \\ = 9 - \frac{1}{16} \\ \\ = \frac{9 \times 16 - 1}{16} \\ \\ = \frac{144 - 1}{16} \\ \\ = \frac{143}{16}$



Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
☺☺

Answer 2

here is your answer...
(9²)¹/² - (4³)_²/3
(9)²/² -(4)^-6/3
9¹-4^-²
9- 1/4²
9-1/16
9/1 - 1/16
=} 143/16