Question

81 a^2−72ab + 16 b^2
factorise

Answer 1

Step-by-step explanation:

$81a^{2} -72ab+16b^{2} =(9a)^{2} -2(9a)(4b)+(4b)^{2} = (9a-4b)^{2}$

Answer = ( 9a - 4b )²

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