Chemistry, asked by stavan2, 9 months ago

(81) At a given temperature, which of the following
solutions will have osmotic pressure equal to that of
0.3 M glucose solution ?
(GUJCET 2012)
(A) 0-1 M Naz (CO(NO2)6]
(B) 0.1 M Naz (Co(H20) (NO2)s]
(C) 0.1 M [Co(H20)3 (NO3)3]
(D) 0.1 M Na (Co(H2O)2 (NO2)4
please give formula ​

Answers

Answered by shwetdeep14
0

Answer:

Molecular weight of Glucose (C

6

H

12

O

6

)=180

Molecular weight of Cane sugar (C

12

H

22

O

11

)=342

Isotonic solutions are the solutions which have same osmotic pressure i.e.., π=iMST

3.42 g of cane sugar in one litre =0.01M

0.18g of glucose in 0. 1 litre which means 1.8g of glucose in 1 litre i.e.., 0.01M.

Here i=1 as both do not dissociate.

π

glucose

=1×0.01×ST=0.01ST

π

canesugar

=1×0.01×ST=0.01ST

If molality is same then the solutions are isotonic.

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