Question

81-E
6
CCE RF & RR
21. If one zero of the polynomial p(x) = x2 - 6x +k is twice the other then
find the value of k
OR​

Answer 1

Given: The equation p(x) = x^2 - 6x + k.

To find: The value of k?

Solution:

• Now we have given the polynomial p(x) = x^2 - 6x + k.

• We have also given that one zero of the polynomial is twice the other.

• Let the first root be a, then second root will be 2a.

• Sum of roots will be:

               a + 2a = -(-6)/1

               3a = 6

               a = 2

• Product of roots will be:

               a.2a = k/1

               2a^2 = k

               2(2)^2 = k

               k = 8

Answer:

            So the value of k is 8.