81.How many times does the 29th day of the month occur in 800 successive years?
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Answered by
7
Answer:
9000 times
Step-by-step explanation:
A leap year (29 days) will occur once in four years. Therefore since there are 800 consecutive years there will be 800 /4 = 200 leap years.
In a leap year 29 occurs in all 12 months.
Therefore in 200 leap years it will be 200 x 12 = 2400 occurrences.
In the non leap years 29 th occurs in 11 months, since February has 28 days. Therefore for 600 years number of occurrences of 29 will be 600 x 11 = 6600.
hence total number of occurrences will be 6600 + 2400 = 9000 times.
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15
Ans.8994 is the answer. The detailed solution given in the solution paper .
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