Question

81. The equivalent mass of Fe in FeO is (Fe = 56)
(1) 56
12) 28
(3) 36
(4) 18.66​

Answer 1

Answer: 2) 28 g

Explanation:

Equivalent weight is calculated by dividing the molecular weight by n factor.  ${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

where n = acidity ,for bases  

n= basicity, for acids

n= valency, for elements

n= cationic charge , for compounds

${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{\text {Charge on iron}}$

$FeO\rightarrow Fe^{2+}+O^{2-}$

${\text{Equivalent weight}}=\frac{56}{2}=28g$

Thus the equivalent mass of Fe in FeO is 28 grams

Answer 2

Answer:

28g

Explanation:

Equivalent weight = Molecular weight/Charge on ion

FeO → Fe^2+ + O^2-

Equivalent weight = 56/2 = 28g