Math, asked by kustwar07, 4 months ago

81(x+1) 2+90(x+1) (y+2) +25(y+2) 2

Answers

Answered by tahashintaj
3

Step-by-step explanation:

Factories form of the expression is 81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1) 2 +90(x+1)(y+2)+25(y+2) 2

=(9x+5y+19)(9x+5y+19)

Step-by-step explanation:

Given : Expression 81(x+1)^2+90(x+1)(y+2)+25(y+2)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2

To find : Factories the expression?

Solution :

The given expression 81(x+1)^2+90(x+1)(y+2)+25(y+2)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2

is in the form of a^2+2ab+b^2a 2 +2ab+b 2

in which

a=9(x+1)a=9(x+1)

b=5(y+2)b=5(y+2)

We know, a^2+2ab+b^2=(a+b)^2a 2 +2ab+b 2

=(a+b) 2

Substitute a and b,

(9(x+1))^2+2(9(x+1))(5(y+2))+(5(y+2))^2=((9(x+1))+(5(y+2)))^2(9(x+1)) 2 +2(9(x+1))(5(y+2))+(5(y+2)) 2

=((9(x+1))+(5(y+2))) 2

81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+9+5y+10)^281(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+9+5y+10)

2

81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2

=(9x+5y+19) 2

81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1)

2

+90(x+1)(y+2)+25(y+2)

2

=(9x+5y+19)(9x+5y+19)

Therefore, factories form of the expression is 81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1)

2+90(x+1)(y+2)+25(y+2) 2

=(9x+5y+19)(9x+5y+19)

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