81^x+27^x=729+3^2x find the value of x
Answers
Answered by
0
Step-by-step explanation:
81^x+27^x=729+3^2x
=>(3)^4×x+(3)^3×x=(3)^6+(3)^2x
=>(3)^4x+(3)^3x=(3)^6+(3)^2x
therefore,take all the powers together
4x+3x=6+2x
=>4x+3x-2x=6
=>7x-2x=6
=>5x=6
=>x=6/5 answer
Similar questions