Math, asked by dafloxiii9269, 11 months ago

81^x+27^x=729+3^2x find the value of x

Answers

Answered by anrav
0

Step-by-step explanation:

81^x+27^x=729+3^2x

=>(3)^4×x+(3)^3×x=(3)^6+(3)^2x

=>(3)^4x+(3)^3x=(3)^6+(3)^2x

therefore,take all the powers together

4x+3x=6+2x

=>4x+3x-2x=6

=>7x-2x=6

=>5x=6

=>x=6/5 answer

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