Math, asked by simarwadhwa1523, 3 months ago

م =
810 Find
mial
zuroes of quadratic polyno
7
85+ بلاو + 55 له​

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Answers

Answered by MrImpeccable
5

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Given:

  •  p(x) = 5\sqrt{5}x^2 + 30x + 8\sqrt{5}

To Find:

  • Zeroes of p(x)

Solution:

 p(x) = 5\sqrt{5}x^2 + 30x + 8\sqrt{5} \\\\\implies p(x) = 0 \\\\\implies 5\sqrt{5}x^2 + 30x + 8\sqrt{5} = 0

 5\sqrt{5}x^2 + 30x + 8\sqrt{5} = 0 \\\\\implies x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\ \text{Here, a = $5\sqrt{5}$, b = 30 and c = $8\sqrt{5}$}

 \\\\\implies x = \dfrac{-30 \pm \sqrt{30^2 - 4(5\sqrt{5})(8\sqrt{5})}}{2(5\sqrt{5})}

\\\\\implies x = \dfrac{-30 \pm \sqrt{900 - 800}}{10 \sqrt{5}}

 \\\\\implies x = \dfrac{-30 \pm 10}{10\sqrt{5}} \\\\\implies x = \dfrac{-3 \pm 1}{\sqrt{5}} \\\\\bf{\implies x = \dfrac{-4*\sqrt{5}}{5} \:\:\:\:\: or\:\:\:\:\: x = \dfrac{-2*\sqrt{5}}{5}}</p><p>

Hope it helps!!

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