Math, asked by therock2312, 9 months ago

√814-8√2163+15√325+√225 plez tell me the answer​


nayan8010: Question is so easy just find the square root of numbers which are under root and then solve them.this is so easy task .
therock2312: ok

Answers

Answered by knjroopa
1

Answer:

0

Step-by-step explanation:

4√81 – 8(3√216 + 15(5√32) + √225   plez tell me the answer

ANSWER

We need to simplify, so  we get

4√81 – 8(3√216 + 15(5√32) + √225

 \sqrt[4]{81} - 8\times\sqrt[3]{216} + 15\times\sqrt[5]{32} + \sqrt{225} \\ \\= \sqrt[4]{3^4}- 8\times\sqrt[3]{6^3} + 15\times\sqrt[5]{2^5} + \sqrt{15^2} \\ \\= 3 - 8\times6 + 15\times2 + 15 \\ \\= 3 - 48 + 30 + 15 \\ \\= 48 - 48\\ \\= 0  

Answered by amitnrw
2

Answer:

\sqrt[4]{81}- 8\times\sqrt[3]{216}+ 15\times\sqrt[5]{32}+\sqrt{225} = 0

Step-by-step explanation:

√814-8√2163+15√325+√225

\sqrt[4]{81} - 8\times\sqrt[3]{216} + 15\times\sqrt[5]{32} + \sqrt{225} \\ \\= \sqrt[4]{3^4}- 8\times\sqrt[3]{6^3} + 15\times\sqrt[5]{2^5} + \sqrt{15^2} \\ \\= 3 - 8\times6 + 15\times2 + 15 \\ \\= 3 - 48 + 30 + 15 \\ \\= 48 - 48\\ \\= 0


knjroopa: I am sorry, I know to use math type, but it does not work.
amitnrw: i believe you missed [tex] & [/tex] in start & end
knjroopa: oh ok thank you...I did not know.....
amitnrw: (3√216 + 15(5√32) remove these brackets also , you have placed by mistake.
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