Question

〖((81g^2 h^4)/(27g^3 h^2 ))〗^(-1) = g/h^ ×1/3h .

Answer 1

Step-by-step explanation:

81g²× h⁴ 27×3 ×h²

_______ = ________ = 3h²/g

27g³× h² 27g

(a/b)^-1= b/a

(3h²/g)^-1 = g/3h² = g/3×h×h = (g/h) *(1/3h)