Question

81p^2-198pq को पूर्ण वर्ग बनाने के लिए क्या जोड़ना पड़ेगा

Answer 1

Assume x is the no. which should be added to factorise it completely

Given

= 81p²-198pq

It can be written as

= (9p)²-2(9p)

Using identity (a-b)²= a²+b²-2ab

where a= 9p
and b is xq
i.e = (9p)²+(xq)²-2(9p)(xq)

Therefore ,

2(9p)(xq)= 198pq
18xpq= 198pq
x= 198/18

Thus x= 11

= (9p)²+(xq)²-2(9p)(xq)
= (9p)²+(11q)²-2(9p)(11q)
= (9p+11q)²

The number which should be added is (11q)² that is 121q²


$hope \: this \: helps \: you$
✌^_^

Answer 2

Answer:

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