Question

{81x^4÷y^-8}^1/4 has simplified valued equal to

Answer 1

$(\frac{81x {}^{4} }{y {}^{ - 8} } ) {}^{ \frac{1}{4} } \\ = (\frac{3 {}^{4} x {}^{4} }{y {}^{ - 8} } ) {}^{ \frac{1}{4} } \\ = \frac{3x}{y {}^{ - 2} } \\ = 3xy {}^{2}$

Answer 2

Step-by-step explanation:

(81x^4) ^1/4÷(y^-8) ^1/4

81x÷y^-2=81x/y^-2