Question

81x square - 625 =0 find the nature of the roots of the following quartic equation. If the real roots exist , find them.

Answer 1

ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ ⓐⓝⓢⓦⓔⓡ

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81x^2-625=0

81x^2=625

x^2=625/81

x=25/9

so,the roots are 25/9