Question

8³^a*2^5*2²^a/4*2^11^a*2¯²^a solve by indices​

Answer 1

Answer:2^(13a-2)

Step-by-step explanation:8³^a×2²^a/4×2⁻²^a = 8^3a×2^2a/2^2×2^-2a

=(2³)^3a×2^2a/2^2×2^-2a

=2^(3×3a) × 2^2a/2^2 × 2^-2a

=2^9a × 2^2a/2^2 × 2^-2a

=2^(9a+2a) / 2^(2+ -2a)

=2^11a/2^(2-2a)

=2^(11a - (2-2a) )

=2^(11a - 2 + 2a)

=2^(13a-2)

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