83. À bike travels 200 m with constant
acceleration and average velocity of 72
km/h. The final velocity acquired by the bike
is 30 m/s Find
a) acceleration of the bike
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Answer:
Given
displacement (s) =200m
Average velocity = 72 kmph=72 x 5/18=20m/s
Average velocity =s/t
20=200/t => t=10s
final velocity (v) =30m/s
we know that
v=u+at. =>u=v-at. =>u=30-10a
s = ut + 1/2at^2
200 = 300 - 100a + 50a
-100 = -50a
a =2m/s^2
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