Question

83. A body is projected with a certain speed at
angles of projection of 8 and 90-e, The
maximum height attained in the two cases are
20m and 10m respectively. The maximum
possible range is
4) 80 m
an m​

Answer 1

Answer:

in simple words the answer is 60

Explanation:

Maximum height in a projectile projected at an angle θ is given by:

H=

2g

u

2

sin

2

θ

.....(1)

H

1

=

2g

u

2

sin

2

θ

=20.....(2)

H

2

=

2g

u

2

sin

2

(90−θ)

=

2g

v

2

cos

2

θ

=10......(3)

H

2

H

1

=tan

2

θ=2......(4)

⇒

2g

u

2

=30

Now, R

max

=

g

u

2

sin2θ

=60sin2θ=60 m (at θ=45

o

)