Question

 (8⁴/³)X(2⁻¹) = ??????????​

Answer 1

Answer:

here is your answer buddy

Step-by-step explanation:

by using this

${a }^{ - x} = ({a}^{x})^{ - 1} \\ = \frac{1}{ {a}^{x} }$

so,

${8}^{ \frac{ - 4}{3} } = ({8}^ \frac{ - 4}{3}) ^{ - 1}$

so that is equal to

$\frac{1}{8 ^ \frac{4}{3} } = \frac{1}{(8 ^{4}) ^ \frac{1}{3} }$

by using the

$a ^{x.y} = (a ^{x})^{y}$

we get

$\frac{1}{(8 \times 8 \times 8 \times 8) ^ \frac{1}{3} } = \frac{1}{(8 ^{3} \times 8) ^ \frac{1}{3} }$

then

$\frac{1}{(8 ^{3}) ^ \frac{1}{3} \times (8) ^ \frac{1}{3} }$

next the three gets cancelled and you will get

$\frac{1}{8 \times \sqrt[3]{8} } = \frac{1}{8 \times 2} = \frac{1}{16}$

in the previous step the cube root of 8 is 2 and you are multiplying it by 8 . 2 you get 16 has the above step mentioned. next is by using the same identity that l used in first also been applied here you will get

$2 ^{ - 2} = (2 ^{2} ) ^{ - 1} = \frac{1}{ {2}^{2} } = \frac{1}{4}$

so by multiplying

$\frac{1}{16} \times \frac{1}{4} = \frac{1}{64}$

so this your final answer

hope you like this answer please thank and mark this as brainliest answer and thank you buddy have a great day.