84 apples are divided between a, b, c in such a way that a gets 7 apples more than b does and b gets 7 apples more than c does. the ratio of their shares is
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a+b+c=84
a+a-7+a-7-7=84
3a=84-21
a=63/3
a=21
hence b=21-7=14
c=14-7=7
hence a:b:c=21:14:7=3:2:1
a+a-7+a-7-7=84
3a=84-21
a=63/3
a=21
hence b=21-7=14
c=14-7=7
hence a:b:c=21:14:7=3:2:1
shivam749:
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Answer:
The ratio of their shares is 5:4:3
Step-by-step explanation:
Given :84 apples are divided between a, b, c in such a way that a gets 7 apples more than b does and b gets 7 apples more than c does
To Find: the ratio of their shares is?
Solution:
Let the share of c be x
We are given that
b gets 7 apples more than c does
So, b's share = x+7
Now we are given that a gets 7 apples more than b
So, a's share = x+7+7=x+14
Now we are given that total apples are 84
So,
So, c's share = 21
b' share = x+7 = 21+7=28
a's share = x+14=21+14=35
So, Ratio of their shares = 35:28:21 = 5:4:3
Hence the ratio of their shares is 5:4:3
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