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Class-X Mathematics
Example-6. In ^PQR, right angle is at Q, PQ = 3 cm and PR = 6 cm. Determine ZQPR and
ZPRQ.
P
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Answer:
Given Below
Step-by-step explanation:
Answer
In ΔPQR; LQ=90
o
PQ=3cm; PR=6cm
QR=
6
2
−3
2
=3
3
sin(LQPR)=
PR
QR
=
6
3
3
=
2
3
So, LQPR=60
o
⇒ LQRP=30
o
.
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