Question

840 students admitted in a school. 2/7 of total students were girls and remaining were boys . 40 girls and 80 boys took part in annual sports
a- what fraction of total girls participated in sports .
b- what fraction of total boys participated in sports ​

Answer 1

Step-by-step explanation:

Given,

Total Students= 840

Total Girls= 2/7 of total students= 840*2/7= 240

∴ Total Boys= 840-240=600

a) Number of girls participated in annual sports= 40

  ∴ Fraction of total girls participated= 40/240= 1/6

b) Number of boys participated in annual sports= 80

  ∴ Fraction of total boys participated= 80/600= 2/15

Hope it helps!!  :)

Answer 2

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✺Answer:

♦️GiveN:

• Total number of students = 840
• 2/7 of total students are girls
• 40 girls and 80 boys participated in annual sports

♦️To FinD:

• What fraction of total girls participated in sports?
• What fraction of total boys participated in sports?

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✺Explanation of Q.

This question is based on appliactions of fractions in which first we have to find the Total number of girls and boys out of all students. Then, we have to divide the number of girls and boys participated in annual sports by their respective totals to get our answers.

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So, Lets solve

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✺Solution:

Total Number of students = 840

No. of girls = 2/7 of total

Then,

$\large{ \rm{ \rightarrow \: no. \: of \: girls = \frac{2}{7} \times 840}} \\ \\ \large{ \rm{ \rightarrow \: no. \: of \: girls = \cancel{\frac{2 \times 840}{7} }}} \\ \\ \large{ \rm{ \rightarrow \: no. \: of \: girls = \boxed{ \purple{ \rm{240 \: girls}}}}}$

Then, No of boys,

$\large{ \rm{ \rightarrow \: no. \: of \: boys = 840 - 240 }} \\ \\ \large{ \rm{ \rightarrow \: no. \: of \: boys = \boxed{ \purple{ \rm{600 \: boys}}}}}$

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a) No. of girls participated in annual sports = 40

Total no. of girls = 240

Fraction of girls participated to total no. of girls,

$\Large{ \rm{ \rightarrow \: \frac{girls \: participated}{total \: no. \: of \: girls} = \cancel{\frac{40}{240} } = \boxed{ \red{\frac{1}{6}}} }}$

b) No. of boys participated in annual sports = 80

Total no. of boys = 600

Fraction of boys participated to total no. of boys,

$\Large{ \rm{ \rightarrow \: \frac{boys \: participated}{total \: no. \: of \: boys} = \cancel{\frac{80}{600}}}} = \boxed{ \red{\frac{2}{15} }}$

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