Question

85. A tank can be filled by pipe X in 2 hrs. and
pipe Y in 6 hrs. At 10 a.m., pipe X was opened. At
what time will the tank be filled if pipe Y is opened
at 11 a.m.?​

Answer 1

Answer:

Step-by-step explanation:

Since pipe x can fill tank in 2 hrs and it was running alone from 10 am to 11 am, it will fill half

Of the tank in 1 hr

Now we only need to fill the remaining half

and both the pipe are running

Let the time be x

So,

1/6x+1/2x=1/2(only for remaining half tank)

x(1/6+1/2)=1/2

x(4/6)=1/2

x=1/2×6/4

x=3/4

x=45 minutes

Hence, tank will be filled at 11:45 am