Question

85. An aqueous solution of acetone contain 29%
acetone by weight. Mole percentage of
acetone in this solution is
(2) 5.55%
(3) 4.04%
(4) 11.25%
(1) 9.09%​

Answer 1

Answer:

4)11.25

Explanation:

29% acetone by weight means 29 gram in 100 g solution

mole percentage(m%)=[(29/60)/(29/60)+(71/18)]×100

m%=(0.4833/4.277)×100

=11.25%

Answer 2

Moles percentage of acetone in the solution is 11.25%

Explanation:

Given: An aqueous solution of acetone contains 29%

To find: Mole percentage of acetone in the solution

Formula used: $Moles percentage = \frac{Moles of acetone}{Total moles}$ × 100

Solution:

29% by weight of aqueous solution of acetone means 29 gm of acetone is present in a 100 g solution mass of solvent($H_{2}O$)

I.e 100 - 29 = 71g

We know that,

$Moles of solute = \frac{mass}{mass of acetone}$

$= \frac{29}{58}$

$= 0.5$

Moles of solute = 0.5

$Moles of solvent = \frac{mass}{mass of acetone}$

$= \frac{71}{18}$

$= 3.94$

Moles of solvent = 3.94

$Moles percentage = \frac{Moles of acetone}{Total moles}$ × 100

$= \frac{0.5}{0.5 +3.94}$ × 100

$= 0.1125 *100$

Moles percentage =11.25 %

Final answer:

Moles percentage of acetone in the solution is 11.25%

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